g^2=0.7

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Solution for g^2=0.7 equation:



g^2=0.7
We move all terms to the left:
g^2-(0.7)=0
We add all the numbers together, and all the variables
g^2-0.7=0
a = 1; b = 0; c = -0.7;
Δ = b2-4ac
Δ = 02-4·1·(-0.7)
Δ = 2.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.8}}{2*1}=\frac{0-\sqrt{2.8}}{2} =-\frac{\sqrt{}}{2} $
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.8}}{2*1}=\frac{0+\sqrt{2.8}}{2} =\frac{\sqrt{}}{2} $

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